x^2-160x+4900=0

Solution for x^2-160x+4900=0 equation:

x^2-160x+4900=0

a = 1; b = -160; c = +4900;
Δ = b2-4ac
Δ = -1602-4·1·4900
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-20\sqrt{15}}{2*1}=\frac{160-20\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+20\sqrt{15}}{2*1}=\frac{160+20\sqrt{15}}{2}
$